C++ Mathematical Expression Toolkit (ExprTk)
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exprtk
exprtk_max_subarray_sum.cpp
Go to the documentation of this file.
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/*
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**************************************************************
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* C++ Mathematical Expression Toolkit Library *
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* *
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* ExprTk Maximum Subarray Problem *
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* Author: Arash Partow (1999-2025) *
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* URL: https://www.partow.net/programming/exprtk/index.html *
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* *
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* Copyright notice: *
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* Free use of the Mathematical Expression Toolkit Library is *
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* permitted under the guidelines and in accordance with the *
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* most current version of the MIT License. *
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* https://www.opensource.org/licenses/MIT *
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* SPDX-License-Identifier: MIT *
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* *
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**************************************************************
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*/
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#include <cstdio>
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#include <string>
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#include "
exprtk.hpp
"
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template
<
typename
T>
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void
max_subarray_sum
()
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{
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typedef
exprtk::symbol_table<T>
symbol_table_t;
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typedef
exprtk::expression<T>
expression_t;
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typedef
exprtk::parser<T>
parser_t;
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const
std::string max_subarray_sum_program =
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" var zero := 0; "
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" var curr_sum := 0; "
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" var curr_start := 0; "
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" "
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" for (var i := 0; i < vec[]; i += 1) "
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" { "
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" curr_sum += vec[i]; "
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" "
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" if (curr_sum < zero) "
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" { "
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" curr_sum := 0; "
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" curr_start := i + 1; "
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" } "
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" else if (curr_sum > max_sum) "
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" { "
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" max_sum := curr_sum; "
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" max_start := curr_start; "
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" max_end := i; "
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" } "
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" } "
;
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T max_sum = T(0);
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T max_start = T(0);
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T max_end = T(0);
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T vec[] = { T(-1), T(-2), T(3), T(5), T(6), T(-2), T(-1), T(4), T(-4), T(2), T(-1) };
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symbol_table_t symbol_table;
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symbol_table.add_variable(
"max_sum"
, max_sum );
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symbol_table.add_variable(
"max_start"
, max_start);
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symbol_table.add_variable(
"max_end"
, max_end );
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symbol_table.add_vector (
"vec"
, vec );
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expression_t expression;
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expression.register_symbol_table(symbol_table);
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parser_t parser;
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parser.compile(max_subarray_sum_program,expression);
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expression.value();
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if
(max_start <= max_end)
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{
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printf(
"Max sum: %10.3f \n"
, max_sum);
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printf(
"Start index: %4d\n"
,
static_cast<
int
>
(max_start));
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printf(
"End index: %4d\n"
,
static_cast<
int
>
(max_end ));
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for
(
int
i =
static_cast<
int
>
(max_start); i <= static_cast<int>(max_end); ++i)
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{
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printf(
"%5.3f "
,vec[i]);
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}
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printf(
"\n"
);
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}
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else
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printf(
"No maximum sum found.\n"
);
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}
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int
main
()
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{
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max_subarray_sum<double>
();
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return
0;
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}
exprtk::expression
Definition
exprtk.hpp:21832
exprtk::parser
Definition
exprtk.hpp:22525
exprtk::symbol_table
Definition
exprtk.hpp:20090
exprtk.hpp
max_subarray_sum
void max_subarray_sum()
Definition
exprtk_max_subarray_sum.cpp:27
main
int main()
Definition
exprtk_max_subarray_sum.cpp:93
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